# Download Design Guide 1: Base Plate and Anchor Rod Design (Second by American Institute of Steel Construction PDF

By American Institute of Steel Construction

Similar design books

Bags: The Modern Classics

Flip your favourite materials right into a style assertion! From stylish wristlets to useful carryalls (and every little thing in between), every one undertaking encompasses a full-sized trend, easy-to-follow directions, and inspirational pictures. all of the stitching fundamentals you would like are the following, and you may study a few extra bold concepts akin to sewing hook-and-loop tapes, making darts and pleats, and attaching magnetic snaps or zippers.

Design and Verification of Microprocessor Systems for High-Assurance Applications

Layout and Verification of Microprocessor structures for High-Assurance purposes Edited by way of: David S. Hardin This ebook examines numerous modern layout and verification applied sciences which were effectively utilized to microprocessor platforms for high-assurance purposes at quite a few degrees – from mathematics circuits to microcode to guide units to working structures to functions.

Plastic Design and Second-Order Analysis of Steel Frames

Plastic layout of metal Frames assesses the present prestige and destiny course of computer-based analyses of inelastic power and balance for direct body layout. It exhibits how layout principles are utilized in useful body layout and gives an advent to the second-order conception of inelastic body layout.

Additional resources for Design Guide 1: Base Plate and Anchor Rod Design (Second Edition)

Example text

0 kips/in. 8 kips/in. 02 in. 46 in. 4 in. Therefore, e < ecrit, and the design meets the criteria for the case of a base plate with small moment. where e is the effective steel reinforcement lap required to develop the load in the reinforcing steel. 2 in. 5. Select 25-in. embedment for anchors. 4. Determine bearing length, Y. 50) = 14 in. , respectively. 7 in. 2 in. The ratio of the concrete to base plate area is unity; Fy of the base plate is 36 ksi and f ′c of the concrete is 4 ksi. Pu = 376 kips/14 in.

Therefore, as noted above, q ≤ qmax. 4, it follows that fp ≤ fp(max). 8 is For moment equilibrium, the line of action of the applied load, Pu, and that of the bearing force, qY must coincide; that is, e = ε. 6) exceeds the maximum value that ε can attain, the applied loads cannot be resisted by bearing alone and anchor rods will be in tension. In summary, for values of e less than εmax, Y is greater than Ymin and q is less than qmax, and obviously, fp is less than fp(max). For values of e greater than εmax, q = qmax.

1. Compute the required strength. 6(1,500) = 3, 600 kip-in. ASD Pa = 100 + 160 = 260 kips M a = 1, 000 + 1,500 = 2 ,500 kip-in. 8 = 355 Since 315 > 306, the inequality Since 315 > 306, the inequality is not satisﬁed. is not satisﬁed. Hence, a larger plate dimension Hence, a larger plate dimension is required. is required. As the second iteration, try a 20 × 20 plate. The increased dimensions cause a modiﬁcation in the maximum bearing pressure, qmax, f, and ecrit. 2 kips/in. 5 in. 5 in. 75 in. 22 in.